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C语言万年历代码

#include"stdio.h" #include"stdlib.h" main( ) { int Year,Month; //年、月 int FirstDay_Year,FirstDay_Month; //某年的第一天是星期几,某年某月的第一天是星期几(范围是0~6,其中0代表星期日) int IsLeapYear; //是否为闰年,0表示不是

#include int monthDay(int,int); int IsLeapYear(int); main() { int days,weekDay,year,month=1,d,i; printf("please input the year:\n"); scanf("%d",&year); days=year-1+(year-1)/400+(year-1)/4-(year-1)/100; while(month

你试一下下面这个代码吧#include #define LMonth 31#define SMonth 30#define VMonth 28typedef enum { Sun, Mon, Jue, Wed, Thu, Fri, Sat} WEEK;typedef enum { January =1, February, Match, Apirl, May, June, July, August, September, October,

# include <stdio.h># define N 2012 int main() { int year_(int x); int month_(int x,int y); void p_(int x,int y,int z); int year,month,year_days,month_days,sum_days; for(;;) { for(;;) { printf("请输入需要查寻的年份:"); scanf("%d",&year); if(year>=

我来写一写~~在VC下编译没错啦,LZ自己去TC编译一下,我没装TC#include <stdio.h>#include <stdlib.h>#include <ctype.h>#include <string.h> void runnian(); void showweek(); int menu_select(); struct ymd { int year; int month; int week; int day; };

#include"stdio.h" void print(int);//函数声明 int dobb(int); int date(int,int,int); void main() { int year=0; printf("输入打印的年份(XXXX)\n"); scanf("%d",&year); print(year); } int dobb(int year)//闰年判断 { if((year%4==0 && year%100!=0)

#include"stdio.h"#define YES 1#define NO 0 int isleap(int year) { int leap=NO; if(year%4==0 && year%100!=0 || year%400==0) leap = YES; return leap; } int week_of_firstday(int year) { int n; n=(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;

/*C语言编写万年历问题 这篇文章主要介绍了C语言实现的一个万年历小程序,相对简单,做C语言日期计算的朋友可以参考下 该程序简单地输入一个年份(1901年之后的年份),随后程序输出该年份十二个月的日历.*/ 1 2 3 4 5 6 7 8 9 10 11

1、闰年的算法: 如果某年能被4整除但不能被100整除, 或者能被400整除,则该年是闰年. 用表达式表示就是(year %4 == 0 && year%100 != 0) || (year%400 == 0)2、计算某一天是星期几:已知e799bee5baa6e79fa5e98193e59b9ee7ad

/*以下程序在TC2 中通过*/#include <stdio.h>#include <conio.h>#include <dos.h> void rili(int,int); int runniansub(int); int week(int,int,int); int monthday[12]={31,28,31,30,31,30,31,31,30,31,30,31}; int main() { struct date d; getdate(&d); printf("今天

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